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The amount of energy approximately be released if all the atoms of 1kg of Deuterium could undergo fusion is (Assume in the fusion of Deu $9 x 10^{13} J$ terium, 0.7% of mass is converted into energy)

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$6 x 10^{27} c a l$

$8 x 10^{23} M e V$

$1.75 x 10^{8} K W H$

$9 x 10^{13} J$

answer is D.

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Detailed Solution

$0.7 % o f 1 k g m a s s c o n v e r t e d i n t o e n e r g y \frac{0.7}{100} x 1 x 9 x 10^{16} J = \frac{0.7}{100} x 1 x 9 x 10^{16} x \frac{1}{3.6 x 10^{6}} K W H = \frac{7}{4} x 10^{8}$

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