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Q.

The amount of energy released by the neutralization of 10ml of 10M aqueous KOH with excess diluted sulphuric acid is Q. Then the enthalpy of neutralization is

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a

-Q 

b

Q

c

10Q 

d

-10Q

answer is C.

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Detailed Solution

10ml of 10M of enthalpy =Q

moleof KOH=MV100=10×101000=0.1

Neutralization enthalpy =

1 mol KOH=10P

Hence the correct answer is (C) 10Q.

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The amount of energy released by the neutralization of 10ml of 10M aqueous KOH with excess diluted sulphuric acid is Q. Then the enthalpy of neutralization is