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The amount of heat flowing in 10 seconds through a copper rod of length 50 cm and area $15 {cm}^{2}$ when the ends are at $100 ° C$ and $0 ° C$ is $(K = 380 {Wm}^{- 1} k^{- 1})$

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1140 J

1260 J

1380 J

1520 J

answer is A.

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Detailed Solution

Q = \frac{KA (θ_{1} - θ_{2}) t}{l}

$= \frac{380 \times 15 \times 10^{- 4} \times 100 \times 10}{0.5} = 1140 J$

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