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Q.

The amount of heat required to melt an ice cube of mass 5 g is

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a

400 cal

b

200 cal

c

100 cal

d

300 cal

answer is B.

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Detailed Solution

$m = 5 g, L = 80 c a l / g = 5 \times 10^{- 3} k g, Q = ? Q = m l = 5 \times 80 Q = 400 c a l ∴ Q = 400 c a l$

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