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Q.

The amount of heat supplied to decrease the volume of an ice water mixture by 1 cm3 without any change in temperature, is equal to: 

(ρice=0.9, ρwater = 80 cal/gm)

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a

360 cal

b

500 cal

c

720 cal

d

None

answer is C.

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Detailed Solution

x gm ice convert into x gm water

  x0.9-x = 1  x = 0.90.1 = 9

 Q = 9 ×80 = 720  cal

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