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Q.

The amount of methane gas is required to obtain 5.6 L of  CO2  gas at STP from the combustion reaction with excess amount of Oxygen gas is present ? 

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An Intiative by Sri Chaitanya

a

4 g

b

32 g

c

12 g

d

8 g

answer is C.

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Detailed Solution

CH4+2O2→CO2+2H2O

1 mole of CH4 ---- 1 mole of CO2

16g of CH4 ----- 22.4 lit of CO2

?X ---- 5.6 lit of CO2

16×5.6=22.4×X

X=16×5.622.4

=4g of CH4

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