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Q.

The amphoteric oxide among V₂O₃, V₂O₄ and V₂O₅ upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

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a

+5

b

+7

c

+3

d

+4

answer is C.

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Detailed Solution

$\begin{aligned} V_{2} O_{5} + alkali \to {VO}_{4}^{3 -} \\ In {VO}_{4}^{3 -} ion, vanadium is in + 5 oxidation state \end{aligned}$

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