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Q.

The amplitude of SHM y=2sin 5πt+2cos πt is

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a

2

b

22

c

4

d

23

answer is D.

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Detailed Solution

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The equation of SHM is y=A sinωt+ϕ or y=Asin ωtcos ϕ+cos ωt sinϕ....(i) The given expression is y=2sin 5πt+2cos πt   ...(ii) Acosϕ=2 and Asinϕ=22 Squaring and adding, we get A=23

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