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Q.

The amplitude of vibration of a particle is given by  am=aoaω2bω+c, where ao, a, b & c are positive. The condition for a single resonant frequency.

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a

b2 = 4ac

b

b2 > 4ac

c

b2 = 5ac

d

b2 < 4ac

answer is A.

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Detailed Solution

for single resonant frequency aw2-bw+c=0                    w = +b±b2-4ac2a                   for single value of  resonant frequency the condition is discriminant =0,                    b2-4ac=0                   b2=4ac

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