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The angle between the circles $x^{2} + y^{2} + 4 x + 8 y = 0 a n d x^{2} + y^{2} + 2 x + 6 y + 8 = 0$ is

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$\frac{π}{4}$

$\frac{π}{6}$

$\frac{2 π}{3}$

$\frac{π}{2}$

answer is B.

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Detailed Solution

$cosθ = \frac{26 - 4 - 24}{2 \sqrt{4 + 16 - 18} \sqrt{1 + 9 - 8}} cosθ = \frac{- 2}{2 . \sqrt{2} \sqrt{2}} = \frac{- 1}{2} cosθ = \cos (π - \frac{π}{3}) θ = \frac{2 π}{3}$

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