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Q.

 The angle between the lines x3y4=0,4yz+5=0 and x+3y11=0,2yz+6=0 is 

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a

60

b

30

c

90

d

45

answer is C.

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Detailed Solution

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 Line x3y4=0=4yz+5 is line of intersection of planes x3y4=0 and 4yz+5=0

Vector along line of intersection is
i^    j^    k^1    3    00    4    1=3i^+j^+4k^=a

 Line x+3y11=0=2yz+6 is line of intersection of planes x+3y11=0 and 2yz+6=0

Vector along line of intersection is
i^j^k^130021=3i^+j^+2k^=bab=(3)(3)+(1)(1)+(4)(2)=0

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