The angle between two circles, each passing through the centre of the other is

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$π$

$\frac{π}{2}$

$\frac{π}{6}$

$\frac{2 π}{3}$

answer is C.

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Detailed Solution

$Here r_{1} = r_{2} = d \Rightarrow \cos θ = \frac{d^{2} - r_{1}^{2} - r_{2}^{2}}{2 r_{1} r_{2}} = \frac{d^{2} - d^{2} - d^{2}}{2 d^{2}} = \frac{- 1}{2} \Rightarrow θ = 120^{0} o r \frac{2 π}{3}$

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