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The angle made by the normal to the curve y = log x where it crosses the x-axis with the x-axis is

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$\frac{π}{2}$

$\frac{3 π}{4}$

$\frac{π}{3}$

$\frac{π}{6}$

answer is B.

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Detailed Solution

$y = 0 \log x = 0 \Rightarrow x = 1$

$∴$ point =(1, 0)

$\frac{dy}{dx} = \frac{1}{x} = \frac{1}{1} = 1 \Rightarrow$ normal slope $= \frac{- 1}{\frac{dy}{dx}}$

$\begin{array}{rcl} = & \frac{- 1}{1} = - 1 \\ \tan & = & - 1 \Rightarrow θ = \frac{3 π}{4} \end{array}$

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