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Q.

The angle of dip at a place is 37° and the vertical component of the earth’s magnetic field is 6 × 10^-5T. The earth’s magnetic field at this
place is (tan 37° = 3/4)

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a

7 × 10^-5 T

b

6 × 10^-5 T

c

5 × 10^-5 T

d

10^-4 T

answer is D.

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Detailed Solution

$\tan δ = \frac{V}{H} = \frac{3}{4} [T A N 37 ° = \frac{3}{4}] V = \frac{3}{4} H V = 6 \times 10^{- 5} T H = \frac{4}{3} \times 6 \times 10^{- 5} T = 8 \times 10^{- 5} T B_{T o t a l = \sqrt{V^{2} + H^{2}} = \sqrt{(36 + 64)} \times 10^{- 5}} = 10 \times 10^{- 5} = 10^{- 4} T$

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