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The angle of elevation of a tower's top from a point 20 metres away is 45 degrees.
The tower's height is______

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10 m

20 m

40 m

$20 \sqrt{3} m$

answer is B.

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Detailed Solution

The angle of elevation is formed by the intersection of the horizontal line and the line of sight.

If the line of sight is directed upward from the horizontal line, the resulting angle is an angle of elevation.

According to the question

$\frac{A B}{B C} = \tan 45 °$

$\Rightarrow \frac{A B}{20} = 1$

$\Rightarrow A B = 20 m$

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