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The angle of the dip at a place is 40.6⁰ and the vertical component of the earth’s magnetic field B_V = 6 ×10^-5T. The total intensity of the earth’s magnetic field at this place is (sin 40.6°= 0.650)

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7 × 10^-5T

9.2 × 10^–5T.

5 × 10^–5T

6 × 10^–5T

answer is D.

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Detailed Solution

$B_{V} = Bsin θ \Rightarrow B = \frac{B_{V}}{\sin θ} = \frac{6 \times 10^{- 5}}{0.65} = 9.2 \times 10^{- 5}$

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