The angle which the vector A=3i^+6j^+2k^ makes with the coordinate axes are

cos − 1 3 7 , cos − 1 6 7 a n d cos − 1 2 7

cos − 1 3 7 , cos − 1 6 7 a n d cos − 1 2 7

cos − 1 4 7 , cos − 1 5 7 a n d cos − 1 3 7

cos − 1 3 7 , cos − 1 4 7 a n d cos − 1 1 7

cos − 1 3 7 cos − 1 3 7 cos − 1 1 7

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

The angle which the vector $A = 3 \hat{i} + 6 \hat{j} + 2 \hat{k}$ makes with the coordinate axes are

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\cos^{- 1} \frac{3}{7}, \cos^{- 1} \frac{6}{7} a n d \cos^{- 1} \frac{2}{7}$

$\cos^{- 1} \frac{4}{7}, \cos^{- 1} \frac{5}{7} a n d \cos^{- 1} \frac{3}{7}$

$\cos^{- 1} \frac{3}{7}, \cos^{- 1} \frac{4}{7} a n d \cos^{- 1} \frac{1}{7}$

$\cos^{- 1} \frac{3}{7} \cos^{- 1} \frac{3}{7} \cos^{- 1} \frac{1}{7}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

$\cos \propto \frac{A_{x}}{A}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE