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Q.

The angles of a triangle are in the ratio 3:5:10. Then the ratio of the smallest side to the greatest side is

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a

1: sin10°

b

1: 2sin 10°

c

1: cos10°

d

1: 2cos10°

answer is D.

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Detailed Solution

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Angles are in the ratio

 A:B:C=3:5:10A=3k,B=5k, C=10k and A+B+C=180°3k+5k+10k=180°k=10°  Angles are 30,50,100

 Smallest side: Greatest side
a:c=2Rsin30:2Rsin100=2Rsin30:2Rsin100 a:c=12:cos10=1:2cos10.

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