The angular acceleration of the toppling pole shown in figure is given by $\alpha =k\sin \theta$, where $\theta$ is the angle between the axis of the pole and the vertical, and $k$ is a constant. The pole starts from rest at $\theta =0$. Choose the correct options.

The centripetal acceleration of the upper end of the pole is $2kl\left(1-\cos \theta \right)$

The tangential acceleration of the upper end of the pole is $lk\sin \theta$

The centripetal acceleration of the upper end of the pole is $lk\sin \theta$

The tangential acceleration of the upper end of the pole is $2kl\left(1-\cos \theta \right)$