The angular deviation of $5^{t h}$ order dark fringe is $12^{\circ}$ in a single slit experiment. If the width of the slit is $9 μ m$ then the wavelength of the incident light is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$5892 \overset{o}{A}$

$3768 \overset{o}{A}$

$6022 \overset{o}{A}$

$4862 \overset{o}{A}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$5^{t h}$ order n=5

$θ = 12^{0}$

We know that, $d \sin θ = n λ, \sin θ \approx θ$

$\Rightarrow d θ = n λ$

Given: $θ = 12 \times \frac{π}{180} r a d i u s$

$λ = \frac{d θ}{n} = \frac{9 \times 10^{- 6} \times 12 \times π}{180 \times 5} = 0.3768 \times 10^{- 6}$

$= 3768 A^{0}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE