The angular frequency of a fan increases from 30 rpm to 60 rpm in π sec . A dust particle is present at a distance of 20 cm from axis of rotation. The tangential acceleration of the particle in π sec is

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0.34 ms^–2

0.8 ms^–2

0.2 ms^–2

1.2 ms^–2

answer is C.

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Detailed Solution

$\begin{array}{l} V_{1} = {rω}_{1} = 0.2 \times 30 \times \frac{π}{30} = 0.2 π {ms}^{- 1} \\ V_{2} = rω 2 = 0.2 \times 60 \times \frac{π}{30} = 0.4 π {ms}^{- 1} \\ a_{t} = \frac{V_{2} - V_{1}}{t} = \frac{0.4 π - 0.2 π}{π} = 0.2 {ms}^{- 2} \end{array}$

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