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Q.

The angular frequency of a simple pendulum is $ω$ rad/sec. Now if the length is made one fourth of the original length, the angular frequency becomes

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a

$2 ω$

b

$4ω$

c

$ω / 2$

d

$ω$

answer is B.

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Detailed Solution

$T = 2 π \sqrt{(\frac{l}{g})} or ω = \frac{2 π}{T} = \sqrt{(\frac{g}{l})} Further . ω_{1} = \sqrt{(\frac{g}{l / 4})} = 2 \sqrt{(\frac{g}{i})} = 2 ω$

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