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Q.

The angular momentum of an electron in a Bohr's orbit of He+  is  3.1652  ×  1034  kgm2/sec. What is the wave number in terms of Rydberg constant (R) of the spectral line emitted when an electron falls from this level to the first excited state.  Use  h=6.626×  1034Js

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a

3R4

b

5R9

c

8R9

d

3R

answer is B.

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Detailed Solution

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Angular  momentum  =nh2π3.1652×  1034  =n×6.626  ×  1034  2π;n=3    v¯=R.Z2.1n121n22;v¯=R.22.12 213 2 =  5R9

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