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Q.

The angular momentum of electron in an excited H atom is $\frac{h}{π}$ . The P.E. of electron will be :

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a

-3.4 eV

b

3.4 eV

c

6.8 eV

d

-6.8 eV

answer is C.

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Detailed Solution

Here;

$n = 2$

$T E = \frac{- 13.6}{2^{2}}$

$P E = 2 T E = - 6.8 eV$

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