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Q.

The angular momentum of the electron in hydrogen atom in the ground state is

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a

$\frac{h}{2 π}$

b

$\frac{h}{2}$

c

2h

d

$\frac{h}{4 π}$

answer is C.

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Detailed Solution

According to Bohr's theory,

Angular momentum, $m v r = \frac{n h}{2 π}$

So in ground state, angular momentum $= \frac{h}{2 π}$

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