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The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration in rad/s² is:

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$12 π$

$2 π$

$4 π$

$104 π$

answer is A.

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Detailed Solution

$\begin{array}{l} α = (\frac{3120 - 1200}{16}) \times \frac{2 π}{60} \\ \frac{1920}{16} \times \frac{2 π}{60} = 4 π \end{array}$

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