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Q.

The angular speed of the wheel of a vehicle is increased from 360 rpm to 1200 rpm in 14 second. Its angular acceleration is,

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a

$2 π rad / s^{2}$

b

$28 π rad / s^{2}$

c

$1 rad / s^{2}$

d

$120 π rad / s^{2}$

answer is B.

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Detailed Solution

$\begin{array}{l} ω_{0} = 360 rpm = 360 \times \frac{2 π}{60} = 12 πrad / s \\ ω = 1200 rpm = 1200 \times \frac{2 π}{60} = 40 πrad / s \\ By ω = ω_{0} + αt \\ 40 π = 12 π + 14 (α) \\ α = \frac{28 π}{14} α = 2 πrad / s^{2} \end{array}$

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