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Q.

The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is _____.
(Assuming the acceleration to be uniform).

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answer is 728.

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Detailed Solution

$θ = (\frac{ω_{1} + ω_{2}}{2}) t When it moves with uniform angular acceleration = (\frac{900 \times \frac{2 π}{60} + 2460 \times \frac{2 π}{60}}{2}) 26 ∴ Number of revolution n = \frac{θ}{2 π} = (\frac{900 + 2460}{60 \times 2}) \frac{2 π (26)}{2 π} = 728$

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