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Q.

The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is _____.
(Assuming the acceleration to be uniform).
 

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answer is 728.

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Detailed Solution

θ=ω1+ω22t When it moves with uniform angular acceleration =900×2π60+2460×2π60226 ∴  Number of revolution n=θ2π =900+246060×22π262π =728

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