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Q.

The angular velocity of earth’s rotation about its axis is ‘ $ω$ ’. An object weighed by a spring balance gives the same reading at the equator as at height ‘h’ above the poles . The value of ‘h’ will be

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a

$\frac{ω^{2} R^{2}}{g}$

b

$\frac{ω^{2} R^{2}}{2 g}$

c

$\frac{2 ω^{2} R^{2}}{g}$

d

$\frac{2 ω^{2} R^{2}}{3 g}$

answer is B.

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Detailed Solution

$F = m g', g' = g - R ω^{2} \cos^{2} ϕ$

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