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Q.

The anion X³⁻ has 18 electrons and its mass number is 31. The number of neutrons present in the nucleus is:


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a

31

b

8

c

18

d

16 

answer is D.

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Detailed Solution

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In the nucleus 16 neutrons are present.
Since it is a Anion,it has gain 3 electrons.So no.of electrons in its atom would be 18-3=15
This means no.of protons are =15
No.of Neutrons = Mass No-No.of protons
                         =31-15
                        ⇒16
 
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The anion X³⁻ has 18 electrons and its mass number is 31. The number of neutrons present in the nucleus is: