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The anion X³⁻ has 18 electrons and its mass number is 31. The number of neutrons present in the nucleus is:

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answer is D.

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Detailed Solution

In the nucleus 16 neutrons are present.
Since it is a Anion,it has gain 3 electrons.So no.of electrons in its atom would be

18 - 3 = 15

This means no.of protons are =15
No.of Neutrons = Mass No-No.of protons

= 31 - 15

\Rightarrow

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