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Q.

The apparent wavelength of light from a star decreases by 0.01% less than the actual wavelength. The velocity of star is.

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a

15Kms^–1moving away from earth

b

15Kms^–1 moving towards the earth

c

30Kms^–1 moving away from earth

d

30Kms^–1 moving towards the earth

answer is D.

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Detailed Solution

$\frac{Δλ}{λ} = \frac{v}{c}; \Rightarrow \frac{0 .01}{100} = \frac{v}{3 \times 10^{8}}; \Rightarrow v = 3 \times 10^{8} \times 10^{- 4} {ms}^{- 1} \Rightarrow v = 3 \times 10^{4} {ms}^{- 1}$
v =30 kms^-1 towards the earth as apparent wave length decreases.

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The apparent wavelength of light from a star decreases by 0.01% less than the actual wavelength. The velocity of star is.