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Q.

The approximate wavelength of a photon of energy 2.48 eV is

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a

$1000 \overset{o}{A}$

b

$2000 \overset{o}{A}$

c

$5000 \overset{o}{A}$

d

$500 \overset{o}{A}$

answer is B.

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Detailed Solution

$By using E (eV) = \frac{12375}{λ (\overset{o}{A})} \Rightarrow λ = \frac{12375}{2 .48} = 4989 .9 \overset{o}{A} \approx 5000 \overset{o}{A}$

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