The aqueous solutions $\text{A}:\left({\text{AgNO}}_3\right)\text{and\hspace{0.17em}B}:\left(\text{LiC}l\right)$  were electrolyzed using Pt electrodes in separate electrolytic cells. The PH of the resulting solutions will

${\text{AgNO}}_3\to {\text{Ag}}^{+}+{\text{NO}}_3^{-}$

${\text{H}}_{\text{2}}\text{O}\to {\text{H}}^{+}+{\text{OH}}^{-}$

$\text{Anode}:2{\text{OH}}^{-}\to {\text{H}}_{\text{2}}\text{O}+\frac{1}{2}{\text{O}}_2+2\stackrel{\Theta }{\text{e}}$

$\text{Cathode}:2{\text{H}}^{+}+2\stackrel{\Theta }{\text{e}}\to {\text{H}}_2$

$\therefore \text{pH}$  decrease due to decrease in ions.

$\text{LiC}l\to {\text{Li}}^{+}+\text{C}{l}^{-}$

${\text{H}}_{\text{2}}\text{O}\to {\text{H}}^{+}+{\text{OH}}^{-}$

$\text{Anode}:2\text{C}{l}^{-}\to \text{C}{l}_2+2\stackrel{\Theta }{\text{e}}$

$\text{Cathode}:2{\text{H}}^{+}+2\stackrel{\Theta }{\text{e}}\to {\text{H}}_2$

$\therefore$ No. of  ${\text{OH}}^{-}$ ions increases so its pH increase.