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The area bounded by the curve $x y^{2} = 1$ and the lines x = 1, x = 2 is

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$4 (\sqrt{2} - 1)$

$4 (\sqrt{2} + 1)$

$2 (\sqrt{2} - 1)$

$2 (\sqrt{2} + 1)$

answer is C.

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Detailed Solution

Given: $x y^{2} = 1$

$R . A = 2 \int_{1}^{2} \frac{1}{\sqrt{x}} d x$

$= 2 (\sqrt{2} - 1)$

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