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Q.

The Area bounded by the curves $y^{2} + 4 x = 4 a n d y - 2 x = 2$ is

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a

$23 / 3$

b

$25 / 3$

c

$9$

d

$22 / 3$

answer is C.

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Detailed Solution

$x = \frac{4 - y^{2}}{4}, x = \frac{y - 2}{2} t h e n, f (y) - g (y) g i v e s \frac{1}{4} (y^{2} + 2 y - 8) t h e n u s e (\frac{Δ^{3 / 2}}{6 a^{2}}) . \frac{1}{4}$

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