The area bounded by the curves $y = 8 - x^{2} a n d 8 x - 4 y + 11 = 0$ is

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$\frac{9}{2}$

$\frac{125}{6}$

$\frac{32}{3}$

answer is A.

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Detailed Solution

$8 - x^{2} = \frac{8 x + 11}{4} \Rightarrow x^{2} + 2 x - \frac{21}{4} = 0 ∆ = b^{2} - 4 a c = 4 + 21 = 25 A r e a = \frac{∆^{\frac{3}{2}}}{6 a^{2}} = \frac{125}{6}$

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