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The area enclosed with in the ellipse $4 x^{2} + 9 y^{2} = 36$ is

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4 π

6 π

9 π

36 π

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Correct option is B

$G i v e n e l l i p s e i s \frac{x^{2}}{9} + \frac{y^{2}}{4} = 1 \Rightarrow a = 3, b = 2 A r e a o f t h e e l l i p s e = π ab = π (3) (2) = 6 π$

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The area enclosed with in the ellipse 4x2+9y2=36 is

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The area enclosed with in the ellipse $4 x^{2} + 9 y^{2} = 36$ is