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The area of 4 walls of a room is $520 m 2$ while its length and breadth are $15$ , and $11 m$ respectively. Find the volume of the room.

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1650 m 3

1850 m 3

1350 m 3

1550 m 3

answer is A.

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Detailed Solution

Given,
Length of room =

15 m

.
Breadth of the room =

11 m

Area of the four walls =

520 m 2

Let height of the room = H
We know that area of four wall of the room is given as:

2 H L + B

520 = 2 (15 + 11) × H ⇒ 520 = 2 × 26 × H ⇒ 520 = 52 H ⇒ H = 52052 ⇒ H = 10

Therefore, from above we see that the height of the room is

10 m

.
Also, we know that the length of the longest rod is given as:

L 2 + B 2 + H 2

Length of longest rod =

(15) 2 + (11) 2 + (10) 2

Length of longest rod =

225 + 121 + 100

Length of longest rod =

446

Now, we will find the volume of the room.
We know that volume of a room (cuboid shape)

= L × B × H

Substituting values in above. We have,

V o l u m e (V) = 15 × 11 × 10 ​ V o l u m e (V) = 1650

Hence, the volume of the room is

1650 m 3

.
So, the correct answer is Option 1.

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The area of 4 walls of a room is 520 m 2 while its length and breadth are 15 , and 11m respectively. Find the volume of the room.

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The area of 4 walls of a room is $520 m 2$ while its length and breadth are $15$ , and $11 m$ respectively. Find the volume of the room.