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The area of a triangle whose sides are 4 cm, 13 cm and 15 cm is

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{cm}^{2}

{cm}^{2}

{cm}^{2}

{cm}^{2}

answer is D.

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Detailed Solution

a = 4, b = 13, c = 15

$S = \frac{a + b + c}{2} = \frac{4 + 13 + 15}{2} = \frac{32}{2} = 16$

Area $(A) = \sqrt{s (s - a) (s - b) (s - c)}$

$= \sqrt{16 \times 12 \times 3 \times 1}$

$= 24 c m^{2}$

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