The area of a circular path is $3850 {\mathrm{m}}^2$. Find its circumference.

Given, the area of a circle is $3850 {\mathrm{m}}^2$.

We know, the area of a circle$= {\mathrm{\pi r}}^2$ (Where $\mathrm{\pi }=\frac{22}{7}$).

${\mathrm{\pi r}}^2 = 3850$

${\mathrm{r}}^2 = \frac{3850}{\mathrm{\pi }}$

${\mathrm{r}}^2 = \frac{3850}{{\displaystyle \frac{ 22}{7}}} = \frac{3850 \times 7}{ 22 }$

${\mathrm{r}}^2 = 1225$

$\mathrm{r} =\surd 1225 = 35 \mathrm{m}$.

So, the circumference of a circle  $= 2\mathrm{\pi r}$

$= 2\times \frac{22}{7} \times 35 = 220 \mathrm{m}$

Therefore, the circumference of a circle is 220 m.