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Q.

The area of a rectangle gets reduced by 80 sq units, if its length is reduced by 5 units and the breadth is increased by 2 units. If we increase the length by 10 units and decrease the breadth by 5 units, then the area is increased by 50 sq units. Find the length and the breadth of the rectangle by the elimination method.


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a

Length =70 units, Breadth =40units

b

Length =20 units, Breadth =10units

c

Length =50 units, Breadth =80units

d

Length =40 units, Breadth =30units 

answer is D.

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Detailed Solution

Given that the area of rectangle reduced by 80 sq. units, when length reduced by 5 units and breadth increased by 2 units and area of rectangle increased by 50 sq. units, when length increased by 10 units and breadth decreased by 5 units
Consider x and y to be the length and the breadth of the rectangle.
Then, the area of a rectangle = xy
According to the given condition,  (x5)(y+2)=xy80 2x5y=70(i) (x+10)(y5)=xy+50 5x+10y=100(ii)  
Multiplying Eq. (i) by 5 and Eq. (ii) by 2 , we get  10x25y=350(iii) 10x+20y=200(iv)  
Adding equations (iii) and (iv), we get  5y=150 y=30  
Substituting the value of y in Eq. (ii), we get  2x5×30=70 x=40  
Therefore, the length =40 units and breadth =30 units.
Hence, option (4) is correct.
 
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