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The area of a rectangular field whose length is twice its breadth, is $2450 m 2$ What is the perimeter of the field?

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200 m

201 m

210 m

211 m

answer is C.

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Detailed Solution

It is given that the area of a rectangular field whose length twice its breadth, is

2450 m 2

.
Area of rectangle = length

\times

breadth.
Perimeter of rectangle = 2(Length + Breadth).
Note the rectangular field's dimensions.
Given that length is equal to double the breadth.
Let length be 2b m and breadth be b m.
Form the equation and solve for b.
Area of rectangle = Length

\times

Breadth =

2 b × b = 2 b 2

square meter.
So, by the given condition,

⇒ 2 b 2 = 2450 ⇒ b 2 = 1225 ⇒ b = 35

So, breadth = 35 m and length = 70 m.
Hence the perimeter of the field,
2(Length + Breadth)

⇒ 2 × (35 + 70) m

⇒ 2 × 105 m = 210 m

As a result, the field's perimeter is 210 meters.
Therefore, option 3 is correct.

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