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Q.

The area of a trapezium is $180 {cm}^{2}$ and its height is 9 cm. If one of the parallel sides is longer than other by 6 cm, the length of the longer of the parallel sides is

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a

17 cm

b

23 cm

c

24 cm

d

18 cm

answer is B.

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Detailed Solution

Let one of the parallel side be x another side will be x + 6
Area of trapezium $\frac{1}{2} \times h \times (a + b) = 180 {cm}^{2}$
$\frac{1}{2} \times 9 \times (x + x + 6) = 180$
$\begin{array}{l} 2 x + 6 = 180 \times \frac{2}{9} \\ x = 17 cm \end{array}$
Longer side is $= x + 6 = 17 + 6 = 23 cm$

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