The area of a triangle whose base and height are 20 cm and 14 cm, is equal to the area of a right triangle whose one side containing the right angle is 10 cm, find the other side.

Given, for the first triangle,

Base = 20 cm

Height = 14 cm

Area = $\frac{1}{2}\times base\times height$

= $\frac{1}{2}\times 20\times 14$

= 140 cm²

Also given,

one side of the second triangle = 10 cm

Area of first triangle = Area of second triangle

140 = $\frac{1}{2}\times 10\times second side$

second side = $\frac{140\times 2}{10}$ = 28 cm