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Q.

The area of a triangle with vertices (a,b+c)  , (b,c+a)   and (c,a+b)   is


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a

2 sq unit

b

0

c

1 sq unit

d

3 sq unit 

answer is B.

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Detailed Solution

It is given that the vertices of the triangle are A a,b+c B b,c+a ,C c,a+b  .
We know that, area of a triangle is given by Area= 1 2 x 1 y 2 − y 3 + x 2 y 3 − y 1 + x 3 y 1 − y 2  .
Here,
x 1 =a,  x 2 =b,  x 3 =c,  y 1 =b+c,  y 2 =c+a, and  y 3 =a+b  .
Then,
Question Image Therefore, the area of the triangle is 0 only.
Hence, option (2) is correct.
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The area of a triangle with vertices (a,b+c)  , (b,c+a)   and (c,a+b)   is