Q.

The area of cross section of the two arms of a hydraulic press are 1cm2and10cm2 respectively (as shown). A force of 5 N is applied on the water in the thinner arm. The force should be applied on the water in thicker arm so that the water may remain in equilibrium is

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a

40 N

b

50 N

c

60 N

d

30 N

answer is C.

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Detailed Solution

A1=1cm2,A2=10cm2,F1=5N                                  

Here pressure is same

P1=F1A1=5

P2=F2A2

F2=P2A2

F2=5×10

F2=50N

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