AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The area of cross-section of the two arms of a hydraulic press are 1 cm² and 10 cm² respectively (fig.). A force of 5 N is applied on the water in the thinner arm. The force should be applied on the water in the thicker arm so that the water may remain in equilibrium _____________ N

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 50.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

According to Pascal's law, the pressure at the same height, or A and B, must be equal for the water to remain in equilibrium.

From the question

$P_{A} = P_{B} \Rightarrow \frac{F_{A}}{A_{A}} = \frac{F_{B}}{A_{B}} \Rightarrow F_{B} = \frac{F_{A}}{A_{A}} \times A_{B}$

$F_{B} = \frac{5 \times 10}{1} = 50 N$

Hence the correct answer is 50N.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!