The area of cross-section of the wider tube shown in the figure is 800 cm2. If a mass of 12 kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is

hρg=mgA;h=mgAρg=mρA=121000×800×10−4=0.15m=15cm

The area of cross-section of the wider tube shown in the figure is 800 cm2. If a mass of 12 kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is

hρg=mgA;h=mgAρg=mρA=121000×800×10−4=0.15m=15cm

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The area of cross-section of the wider tube shown in the figure is 800 cm². If a mass of 12 kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is

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6 cm

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15 cm

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answer is C.

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$h ρ g = \frac{mg}{A}; h = \frac{mg}{A ρ g} = \frac{m}{ρ A}$

$= \frac{12}{1000 \times 800 \times 10^{- 4}} = 0.15 m = 15 cm$

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The area of cross-section of the wider tube shown in the figure is 800 cm2. If a mass of 12 kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is

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The area of cross-section of the wider tube shown in the figure is 800 cm². If a mass of 12 kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is