The area of plates of a parallel plate condenser is A and the distance between the plates is 10mm. Two dielectric sheets one of dielectric constant 10 and thickness 6mm and the other of dielectric constant 5 and thickness 4mm are placed parallel to the plates, in a capacitor. The capacity of the condenser is

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$\frac{5000}{7} ε_{0} A$

$\frac{12}{35} ε_{0} A$

$\frac{2}{3} ε_{0} A$

$1500 ε_{0} A$

answer is C.

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Detailed Solution

$C = \frac{ε_{0} A}{(\frac{t_{1}}{k_{1}} + \frac{t_{2}}{k_{2}})} = \frac{ε_{0} A}{\frac{6 \times 10^{- 3}}{10} + \frac{4 \times 10^{- 3}}{5}} = \frac{5000}{7} ε_{0} A$

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