AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The area of quadrilateral ABCD where BD=24cm, AL=5cm, CM=8cm and AL and CM are perpendicular to BD is [[1]].

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 156 C M 2.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The area of quadrilateral ABCD where BD=24cm, AL=5cm, CM=8cm and AL and CM are perpendicular to BD is

156 c m 2

.
We are given that in quadrilateral ABCD, BD=24cm, AL=5cm, CM=8cm and AL and CM are perpendicular to BD.
Also, we can see that area of quadrilateral ABCD=Area of triangle DAB + Area of triangle DCB.
Area of triangle=

12 × b × h

, where b is base and h is height.
So, in triangle DAB, DB=24cm and AL=5cm.
Area of triangle DAB=

12 × D B × A L

= 12 × 24 × 5 c m

= 60 c m 2

Likewise, in triangle DCB, DB=24cm and CM=8cm.
Area of triangle DCB

= 12 × D B × C M

= 12 × 24 × 8

= 96 c m 2

Thus, the area of the quadrilateral is

60 + 96 c m 2 = 156 c m 2

.
Hence, the correct answer is

156 c m 2

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!